**Core Concept**
The question is testing the student's understanding of asymmetric carbon atoms, also known as chiral centers, in organic chemistry. Asymmetric carbon atoms are crucial in the field of pharmacology, as they contribute to the stereochemistry of drugs and their interactions with biological molecules.

**Why the Correct Answer is Right**
An asymmetric carbon atom is a carbon atom that is bonded to four different groups, resulting in a non-superimposable mirror image. In other words, if you try to superimpose a molecule on its mirror image, they will not match. The correct answer is a compound that does not have this property. For example, **Option C: Ethanol (CH3CH2OH)** has no asymmetric carbon atom because the two hydrogen atoms on the second carbon atom are equivalent, making it not a chiral center.

**Why Each Wrong Option is Incorrect**
* **Option A:** Methanol (CH3OH) has an asymmetric carbon atom because the hydrogen atom on the second carbon atom is different from the hydroxyl group.
* **Option B:** 2-Propanol (CH3CH(OH)CH3) has an asymmetric carbon atom because the two methyl groups on the second carbon atom are different.
* **Option D:** Glucose (C6H12O6) has multiple asymmetric carbon atoms, making it chiral.

**Clinical Pearl / High-Yield Fact**
In pharmacology, understanding the stereochemistry of drugs is crucial because small changes in the three-dimensional structure of a molecule can significantly affect its activity and toxicity.

**Correct Answer: C. Ethanol (CH3CH2OH)**