**Core Concept**
Hoffmann elimination is a type of metabolic reaction that involves the removal of a methyl group from a tertiary amine, resulting in the formation of a secondary amine and a tertiary amine's methyl group is converted to a carbocation, which then gets eliminated as a volatile compound, typically a tertiary amine's methyl group is converted to a carbocation, which then gets eliminated as a volatile compound, often as a tertiary amine's methyl group is converted to a carbocation, which then gets eliminated as a volatile compound, often through the process of Hoffmann elimination.

**Why the Correct Answer is Right**
This process is particularly relevant for certain tertiary amines, such as procainamide and lidocaine. The mechanism of Hoffmann elimination involves the formation of a carbocation, which is then eliminated as a volatile compound, often methanol or dimethylamine. This reaction is favored in alkaline conditions, which is why it's often seen in the presence of a base. The resulting secondary amine is often pharmacologically active, while the eliminated compound may be toxic.

**Why Each Wrong Option is Incorrect**
**Option A:** Not a relevant compound for Hoffmann elimination.
**Option B:** Not a common example of Hoffmann elimination.
**Option C:** Not a compound that undergoes Hoffmann elimination.

**Clinical Pearl / High-Yield Fact**
Hoffmann elimination is an important consideration in the metabolism of certain tertiary amines, and understanding this reaction can help clinicians predict potential side effects and toxicity.

**Correct Answer:** B. Procainamide