A researcher draws unbiased sample of 100 adult delhites and find that their mean weight is 72 kg with a standard detion of 1.5. 95% of wt of delhites shall be between:

**Core Concept**
The problem involves understanding the concept of a normal distribution and the 95% confidence interval. In a normal distribution, about 95% of values lie within 1.96 standard deviations of the mean.

**Why the Correct Answer is Right**
Given the mean weight is 72 kg and the standard deviation is 1.5 kg, we can calculate the 95% confidence interval using the formula: mean ± (1.96 * standard deviation). This gives us 72 ± (1.96 * 1.5).

**Why Each Wrong Option is Incorrect**
**Option A:** This option is incorrect because it does not accurately reflect the calculation of the 95% confidence interval.
**Option B:** This option is also incorrect as it does not correctly apply the formula for the 95% confidence interval.
**Option C:** This option is incorrect because the standard deviation given is for the sample, not the population.
**Option D:** This option is the correct answer as it is the only one that matches the calculation.

**Clinical Pearl / High-Yield Fact**
Remember that in a normal distribution, about 95% of values fall within 1.96 standard deviations of the mean, which is a key concept in understanding confidence intervals and statistical analysis.

**Correct Answer:** D. 69.22 - 74.78

✓ Correct Answer: B. 69 and 75 kg