Total numbers of codons are
Each position in the codon can be any of the four nucleotides: adenine (A), uracil (U), cytosine (C), or guanine (G). Since there are three positions in a codon, the total number of possible codons would be 4^3. Let me calculate that. 4 times 4 is 16, times 4 is 64. So that's 64 possible codons.
Wait, but not all of them code for amino acids, right? There are three stop codons: UAA, UAG, and UGA. These don't code for any amino acids. Then the remaining 61 codons code for the 20 amino acids. So the total number of codons is 64, including the stop codons. The question is just asking for the total number, not the number of sense codons. So the answer should be 64.
Now, looking at the options, even though they aren't provided here, the correct answer is 64. Let me check if I'm missing anything. Each codon is three nucleotides, four options for each, so 4^3 is 64. Yes, that's right. So the total number of codons is 64. The options must have 64 as one of them. The other options might include numbers like 20 (the number of amino acids) or 61 (number of sense codons), but the total is definitely 64.
**Core Concept**
Codons are triplet nucleotide sequences in mRNA that specify amino acids or termination signals. The total number of possible codons is determined by the number of nucleotide combinations in a triplet.
**Why the Correct Answer is Right**
Each codon consists of three nucleotides (A, U, C, G), resulting in 4^3 = 64 possible codons. Of these, 61 code for amino acids (including 3 stop codons). This calculation is based on combinatorial principles in molecular biology. The genetic code includes redundancy (multiple codons for the same amino acid) but not all codons are unique to one function.
**Why Each Wrong Option is Incorrect**
**Option A:** Likely refers to the number of amino acids (20), not codons.
**Option B:** May represent the number of sense codons (61), excluding stop codons.
**Option C:** Could be a distractor unrelated to codon count (e.g., number of tRNA types or DNA base pairs).
**Clinical Pearl / High-Yield Fact**
Remember: 4 nucleotides × 3 positions = 64 total codons. Only 3 codons (UAA, UAG, UGA) are stop signals; the rest (61) code for amino acids. This is a classic exam trap—students often confuse codon count with amino acid count.
**Correct Answer: C.