Fall in alkalinity of Ca(OH)2 wheh used as a root canal dressing starts at
**Core Concept**
When used as a root canal dressing, calcium hydroxide (Ca(OH)2) undergoes a chemical reaction that affects its alkalinity. This reaction is crucial for understanding the properties and limitations of Ca(OH)2 in endodontic procedures.
**Why the Correct Answer is Right**
Calcium hydroxide reacts with the moisture in the canal to form calcium hydroxide gel, which is less alkaline than its powder form. This reaction starts to occur within a week, leading to a decrease in the alkalinity of Ca(OH)2. The gel formation is due to the interaction of Ca(OH)2 with water, resulting in the release of hydroxide ions. This decrease in alkalinity is significant because Ca(OH)2's antibacterial properties and ability to dissolve organic matter are reduced in its gel form.
**Why Each Wrong Option is Incorrect**
**Option B:** 2 weeks - While the reaction is ongoing, the decrease in alkalinity is not as pronounced at 2 weeks, and the gel formation is not yet complete.
**Option C:** 4 weeks - By 4 weeks, the gel formation is well-established, but the alkalinity may not have decreased significantly enough to be the primary concern.
**Option D:** 12 weeks - At this point, the Ca(OH)2 has fully converted to its gel form, and the alkalinity decrease would be more pronounced.
**Clinical Pearl / High-Yield Fact**
It is essential to note that the reaction of Ca(OH)2 with moisture can lead to a decrease in its effectiveness as an antibacterial agent and a root canal dressing. This is why Ca(OH)2 is typically used for short periods, and its effects should be monitored closely.
**✓ Correct Answer: A. 1 week**