Metal required for polymerization of insulin is:
**Core Concept**
The polymerization of insulin is a critical step in the formation of amyloid fibrils, which are associated with various diseases, including type 2 diabetes and amyloidosis. This process involves the aggregation of insulin molecules, leading to the formation of insoluble fibrils. The metal ions play a crucial role in this process by facilitating the formation of insulin dimers and higher-order oligomers.
**Why the Correct Answer is Right**
Zinc ions (Zn2+) are essential for the polymerization of insulin. They bind to specific sites on the insulin molecule, promoting the formation of insulin dimers and higher-order oligomers. This binding is essential for the insulin to be stored in the pancreas in a hexameric form, which is more stable than the monomeric form. The presence of zinc ions also facilitates the formation of amyloid fibrils, which are characteristic of various diseases.
**Why Each Wrong Option is Incorrect**
**Option A:**
This option is incorrect because there is no evidence to suggest that copper ions are involved in the polymerization of insulin.
**Option B:**
This option is incorrect because magnesium ions are not directly involved in the polymerization of insulin.
**Option C:**
This option is incorrect because calcium ions are not typically associated with the polymerization of insulin.
**Clinical Pearl / High-Yield Fact**
The formation of amyloid fibrils is a hallmark of various diseases, including type 2 diabetes and amyloidosis. The presence of zinc ions in the pancreas is essential for the storage of insulin in a hexameric form, which is more stable than the monomeric form.
**Correct Answer:** D. Zinc ions.