Medical MCQ-In a population of 100 prevalence of candida glabrata was found to be 80%. If the investigator has to repeat the prevalence with 95% confidence what will the prevalence be

In a population of 100 prevalence of candida glabrata was found to be 80%. If the investigator has to repeat the prevalence with 95% confidence what will the prevalence be

78-82%

72-88%

76-84%

74-86%

Question Category:

Social & Preventive Medicine

Correct Answer:

72-88%

Description:

Confidence Intervals for Population proportions (For 95% Confidence) CI = P + 2 SEP = P + 2 √pq/n Here, P=0.80 (80%); p=0.80; q= 1-p = 1-0.80 = 0.20; n=100 CI = 0.80 + 2 √0.8*0.2/100 = 0.80 + 0.08 = 0.72, 0.88 (72%, 88%)

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