Elimination of waste product from a normal person requires minimal amount of urine of
Correct Answer: 500 ml
Description: Ans. (b) 500 ml(Ref: Ganong, 25th ed/p.685)A normal 70kilogram human must excrete about 600mOsm of solute every dayWe know that the maximum concentrating ability of kidney is 1200mOsmSo, the minimal volume of urine that must be excreted is 600/1200=0.5L/day or 500 ml/dayThis 500 ml/day is needed to excrete 600mOsm of solute
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