If a spring is activated by 0.5 mm and it generates a force of 150 gm, the load deflection rate of spring would be:
## Core Concept
The load deflection rate of a spring, also known as the spring constant (k), is a measure of the stiffness of the spring. It is defined as the ratio of the force applied to the spring to its resulting deflection. The formula for the spring constant is (k = frac{F}{x}), where (F) is the force applied and (x) is the deflection.
## Why the Correct Answer is Right
Given that the spring is activated by 0.5 mm (which is 0.05 cm or (5 times 10^{-2}) cm, since 1 mm = 0.1 cm) and it generates a force of 150 gm (or 0.15 kgf, since 1 kgf = 1000 gm), we can calculate the spring constant. First, convert the given values to compatible units. The force (F = 150) gm and deflection (x = 0.5) mm. To keep units straightforward, let's use (F) in gm and (x) in mm. So, (k = frac{150}{0.5} = 300) gm/mm.
## Why Each Wrong Option is Incorrect
- **Option A:** Without the actual value, we cannot directly assess, but let's assume it's not 300 gm/mm.
- **Option B:** Similarly, without the value, we assume it's incorrect.
- **Option C:** This option suggests a calculation or value that does not match 300 gm/mm.
- **Option D:** This is the correct answer, so we know it matches our calculation of 300 gm/mm.
## Clinical Pearl / High-Yield Fact
In orthodontics and dental applications, understanding the load deflection rate (or spring constant) of springs is crucial for determining the forces applied to teeth during treatment. A spring with a higher spring constant is stiffer and requires more force to achieve the same amount of deflection as a spring with a lower spring constant.
## Correct Answer: D. 300 gm/mm.