On ECG, ST segment elevation is seen in all of the following conditions EXCEPT:
**Core Concept**
ST segment elevation (STE) on an electrocardiogram (ECG) indicates abnormal electrical activity in the heart, often due to ischemia, injury, or inflammation. STE is characterized by a sudden upward deflection of the ST segment from the baseline, which can be a sign of acute coronary syndrome, myocardial infarction, or pericarditis.
**Why the Correct Answer is Right**
ST segment elevation is a hallmark of pericarditis, where inflammation of the pericardium (the sac surrounding the heart) leads to electrical changes in the heart. The ST segment elevation in pericarditis is typically concave upwards and can be accompanied by other ECG changes such as PR segment depression and widespread ST elevation. This is due to the involvement of the entire pericardium and the subsequent electrical activation of the heart.
**Why Each Wrong Option is Incorrect**
* **Option A:** Acute myocardial infarction (AMI) is a condition where STE is a common finding, often indicative of ST-elevation myocardial infarction (STEMI). The STE in AMI is typically convex upwards and can be accompanied by other ECG changes such as Q waves and T wave inversion.
* **Option B:** Pulmonary embolism (PE) can cause STE in the right precordial leads (V1-V4), often referred to as right ventricular strain. This is due to the increased pressure and strain on the right ventricle, leading to electrical changes in the heart.
* **Option C:** Hypokalemia (low potassium levels) can cause ST segment depression, not elevation. This is due to the abnormal electrical activity in the heart caused by the potassium imbalance.
**Clinical Pearl / High-Yield Fact**
In the context of STE, it's essential to remember that the location and morphology of the ST elevation can provide valuable clues to the underlying diagnosis. For example, STE in leads V1-V4 is often associated with pericarditis, while STE in leads II, III, and aVF may indicate inferior wall myocardial infarction.
**Correct Answer:** D. Hypokalemia.