Fluoride, used in the collection of blood samples for glucose estimation, inhibits the enzyme:
First, the core concept here is the preservation of blood glucose levels. When blood is collected, glucose starts to metabolize, which can lower the measured levels if not prevented. Fluoride is an anticoagulant and preservative, so it must inhibit an enzyme involved in glycolysis to stop this breakdown.
The enzyme in glycolysis that's inhibited by fluoride is enolase. Enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate. Fluoride forms a complex with magnesium and enolase, inhibiting the enzyme. This stops glycolysis, preserving glucose levels in the sample.
Now, looking at the options (even though they're not provided), the correct answer would be enolase. The other options might be other enzymes in glycolysis like hexokinase, phosphofructokinase, or pyruvate kinase. Each of these has different roles and isn't inhibited by fluoride. For example, hexokinase is inhibited by glucose-6-phosphate, not fluoride. Phosphofructokinase is regulated by ATP and citrate. Pyruvate kinase is inhibited by ATP and alanine. So those are the incorrect options.
The clinical pearl here is that fluoride in blood collection tubes prevents glycolysis by inhibiting enolase, which is crucial for accurate glucose measurement. If a sample isn't preserved properly, the glucose levels will be falsely low due to ongoing metabolism.
I need to structure the explanation with the required sections, making sure each part is concise and fits within the character limit. Also, use bold for section headers and key terms. Check that each incorrect option is addressed properly. Make sure the clinical pearl is a high-yield fact that students should remember for exams.
**Core Concept**
Fluoride in blood collection tubes inhibits glycolysis to prevent glucose degradation. This is critical for accurate glucose estimation, as unchecked glycolysis lowers measured levels. The enzyme targeted is central to the glycolytic pathway.
**Why the Correct Answer is Right**
Fluoride inhibits **enolase**, an enzyme in glycolysis that catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate. By binding to magnesium (Mg²⁺) and enolase, fluoride forms a complex that blocks this step, halting glycolysis. Without enolase activity, glucose metabolism stops, preserving blood glucose levels for accurate testing.
**Why Each Wrong Option is Incorrect**
**Option A:** *Hexokinase* is inhibited by glucose-6-phosphate, not fluoride. It acts earlier in glycolysis and is not the target of fluoride.
**Option B:** *Phosphofructokinase* (PFK) is regulated by ATP/citrate, not fluoride. Its inhibition would require different agents like ATP or fructose-1,6-bisphosphate.
**Option C:** *Pyruvate kinase* is inhibited by ATP/alanine, not fluoride. Fluoride’s action occurs upstream of this enzyme.
**Clinical Pearl / High-Yield