Antidote used in methyl alcohol poisoning is?
## Core Concept
Methyl alcohol (methanol) poisoning is a serious condition that requires prompt treatment. Methanol itself is not highly toxic, but its metabolites, formaldehyde and formic acid, are highly toxic. The goal of treatment is to prevent the conversion of methanol to these toxic metabolites.
## Why the Correct Answer is Right
The correct answer, **Fomepizole**, is an antidote for methanol poisoning. Fomepizole works by inhibiting **alcohol dehydrogenase**, the enzyme responsible for converting methanol into formaldehyde and then formic acid. By blocking this enzyme, fomepizole effectively reduces the formation of the toxic metabolites of methanol, thereby reducing the severity of the poisoning.
## Why Each Wrong Option is Incorrect
- **Option A:** This option is blank and does not provide any information.
- **Option B:** This option is also blank and does not provide any information.
- **Option C:** This option is blank as well and does not offer any relevant information.
- **Option D:** Ethanol is indeed used as a treatment for methanol poisoning because it competitively inhibits alcohol dehydrogenase, similar to fomepizole. However, it is not the correct answer in this context because fomepizole is specifically listed and is a more modern and targeted therapy.
## Clinical Pearl / High-Yield Fact
A key point to remember is that in methanol poisoning, **fomepizole is a specific antidote** that can be used alongside supportive care and hemodialysis in severe cases. Fomepizole has a higher affinity for alcohol dehydrogenase than methanol, making it an effective treatment to prevent the metabolism of methanol to its toxic metabolites.
## Correct Answer: D. Fomepizole