How many base pairs are encoded by a prokaryotic polypeptide of 250 amino acids?
**Core Concept**
The question tests the understanding of the genetic code and how amino acids are encoded by DNA base pairs. Each amino acid is encoded by a sequence of three nucleotides, known as a codon.
**Why the Correct Answer is Right**
Since each amino acid is encoded by three nucleotides, a polypeptide of 250 amino acids would require 250 codons. With each codon consisting of three base pairs, the total number of base pairs required would be 250 * 3 = 750.
**Why Each Wrong Option is Incorrect**
**Option A:** This option is incorrect because it underestimates the number of base pairs required.
**Option B:** This option is also incorrect as it does not accurately reflect the calculation of base pairs.
**Option D:** This option overestimates the number of base pairs required.
**Clinical Pearl / High-Yield Fact**
The genetic code is nearly universal, with the same codons encoding the same amino acids in nearly all organisms.
**Correct Answer:** C. 750 base pairs