A patient inhales a tidal volume of 500 mL. The intrapleural pressure was measured as – 4 cm of water before inspiration and – 9 cm of water after inspiration. Calculate the pulmonary compliance in this patient:
Correct Answer: 0.1 L/cm
Description: Answer- A. 0.1 L/cmThe pulmonary compliance in this patient is 0.1 L/cm H2O.Measure of the lung's ability to stretch & expand (distensibility of elastic tissue).Pulmonary surfactant increases compliance by decreasing the surface tension of water.Pulmonary compliance = DV/ DB
Category:
Physiology
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