A patient’s urine is collected for 2 hours, and the total volume is 600 milliliters during this time. Her urine osmolarity is 150 mOsm/L, and her plasma osmolarity is 300 mOsm/L. What is her “free water clearance”?
Correct Answer: +2.5 ml/min
Description: Free water clearance is calculated as: urine flow rate (600 ml/2 h, or 5 ml/min) - osmolar clearance (urine osmolarity x urine flow rate/plasma osmolarity). Therefore, free water clearance is equal to +2.5 ml/min.
Category:
Physiology
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