Gram stained periorbital exudates in severe panophthalmitis with cellulitis in an elderly diabetic shows irregular branching aseptate and broad hyphae. Which of the following is the most likely diagnosis-
Correct Answer: Apophysomyces species
Description: 1.Irregular branching aseptate and broad hyphae belong to Zygomycota phylum and cause Zygomycosis. *Zygomycota are aseptate fungi that cause serious infections, primarily in ketoacidotic diabetic patients and cancer patients. 2. Agents of Zygomycosis - - Rhizopus, Mucor, Lichtheimia (Old name: Absidia), Apophysomyces - Candida: Yeast like fungi. - Aspergillus: Narrow septate hyaline hyphae with acute angle branching molds. - Pencillium: Hyaline thin septate hyphae, vesicles are absent, and conidia arranged as brush border appearance molds.
Category:
Microbiology
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